\[ - \frac{4a - 8b}{16b^2 - 4a^2} \]
Lösung anzeigen
Lösung
\[ - \frac{4(a - 2b)}{4(b^2 - a^2)} = - \frac{a - 2b}{b^2 - a^2} = - \frac{a - 2b}{(2b - a)(2b + a)} = \frac{2b - a}{(2b - a)(2b + a)} = \frac{1}{2b + a} \]